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考题17-18 2015 AMC 10B

2018-08-06 重点归纳

AMC10数学竞赛是美国高中数学竞赛中的一项,是针对高中一年级及初中三年级学生的数学测试,该竞赛开始于2000年,分A赛和B赛,于每年的2月初和2月中举行,学生可任选参加一项即可。不管是对高校申请还是今后在数学领域的发展都极其有利!那么接下来跟随小编来看一下AMC10的官方真题以及官方解答吧:

Problem 17

The centers of the faces of the right rectangular prism shown below are joined to create an octahedron. What is the volume of this octahedron?

考题17-18 2015 AMC 10B

考题17-18 2015 AMC 10B

Solution

The octahedron is just two congruent pyramids glued together by their base. The base of one pyramid is a rhombus with diagonals $4$and $5$, for an area $A = 10$. The height $h$, of one pyramid, is $\dfrac{3}{2}$, so the volume of one pyramid is $\dfrac{Ah}{3}=5$. Thus, the octahedron has volume $2\cdot5=\boxed{(B)\\10}$

Problem 18

Johann has $64$ fair coins. He flips all the coins. Any coin that lands on tails is tossed again. Coins that land on tails on the second toss are tossed a third time. What is the expected number of coins that are now heads?

考题17-18 2015 AMC 10B

Solution

Every time the coins are flipped, half of them are expected to turn up heads. The expected number of heads on the first flip is $32$, on the second flip is is $16$, and on the third flip it is $8$. Adding these gives $\boxed{\mathbf{(D)}\ 56}$

以上就是小编对AMC10数学竞赛试题以及解析的介绍,希望对你有所帮助,更多学习资料请持续关注AMC数学竞赛网